Advertisements
Advertisements
प्रश्न
AD and BC are equal perpendiculars to a line segment AB (See the given figure). Show that CD bisects AB.

Advertisements
उत्तर
In △BOC and △AOD,
∠OBC = ∠OAD ...[Each 90° (Given)]
∠BOC = ∠AOD ...[Vertically opposite angles]
BC = AD ...[Given]
∴ △BOC ≌ △AOD ...[By AAS congruence rule]
⇒ OB = OA ...[Corresponding parts of congruent triangles]
i.e., O is the mid-point of AB.
So, CD bisects the line segment AB.
APPEARS IN
संबंधित प्रश्न
AB is a line segment and P is its mid-point. D and E are points on the same side of AB such that ∠BAD = ∠ABE and ∠EPA = ∠DPB (See the given figure). Show that
- ΔDAP ≅ ΔEBP
- AD = BE

Which congruence criterion do you use in the following?
Given: ZX = RP
RQ = ZY
∠PRQ = ∠XZY
So, ΔPQR ≅ ΔXYZ

In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that ΔADC ≅ ΔCBA.
The given figure shows a circle with center O. P is mid-point of chord AB.

Show that OP is perpendicular to AB.
The following figure shows a circle with center O.

If OP is perpendicular to AB, prove that AP = BP.
In the given figure: AB//FD, AC//GE and BD = CE;
prove that:
- BG = DF
- CF = EG

In the following figure, AB = AC and AD is perpendicular to BC. BE bisects angle B and EF is perpendicular to AB.
Prove that : ED = EF

In the following figures, the sides AB and BC and the median AD of triangle ABC are equal to the sides PQ and QR and median PS of the triangle PQR.
Prove that ΔABC and ΔPQR are congruent.
![]() |
![]() |
In quadrilateral ABCD, AD = BC and BD = CA.
Prove that:
(i) ∠ADB = ∠BCA
(ii) ∠DAB = ∠CBA
In the following figure, OA = OC and AB = BC.
Prove that: ΔAOD≅ ΔCOD


