Advertisements
Advertisements
प्रश्न
A sweet is in the shape of rhombus whose diagonals are given as 4 cm and 5 cm. The surface of the sweet should be covered by an aluminum foil. Find the cost of aluminum foil used for 400 such sweets at the rate of ₹ 7 per 100 sq.cm
Advertisements
उत्तर
Diagonals d1 = 4 cm and d2 = 5 cm
Area of one rhombus shaped sweet = `1/2` (d1 × d2) sq.units
= `1/2` × 4 × 5 cm2
= 10 cm2
Aluminum foil used to cover 1 sweet = 10 cm2
∴ Aluminum foil used to cover 400 sweets = 400 × 10 = 4000 cm2
Cost of aluminum foil for 100 cm2 = ₹ 7
∴ Cost of aluminum foil for 4000 cm2 = `4000/100 xx 7` = ₹ 280
∴ Cost of aluminum foil used = ₹ 280.
APPEARS IN
संबंधित प्रश्न
If perimeter of a rhombus is 100 cm and length of one diagonal is 48 cm, what is the area of the quadrilateral?
Find the area of a rhombus whose diagonals are of lengths 10 cm and 8.2 cm.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 26 m | 468 sq.m |
The area of a rhombus is 100 sq.cm and length of one of its diagonals is 8 cm. Find the length of the other diagonal
The area of the rhombus with side 4 cm and height 3 cm is
The height of the rhombus whose area 96 sq.m and side 24 m is
One of the diagonals of a rhombus is thrice as the other. If the sum of the length of the diagonals is 24 cm, then find the area of the rhombus.
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.

Area of a rhombus = `1/2` product of ______.
Most of the sailboats have two sails, the jib and the mainsail. Assume that the sails are triangles. Find the total area sail of the sailboats to the nearest tenth.

