Advertisements
Advertisements
प्रश्न
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is ______.

विकल्प
72 cm2
36 cm2
24 cm2
18 cm2
Advertisements
उत्तर
The figure ABCD is a quadrilateral in which AB = CD and BC = AD. Its area is 36 cm2.
Explanation:

It is clear from the figure that, quadrilateral ABCD is a parallelogram. The diagonal AC of the given parallelogram ABCD divides it into two triangles of equal areas.
Area of the ΔABC = `1/2 xx "Base" xx "Height"`
= `1/2 xx 12 xx 3`
= 18 cm2
∴ Area of parallelogram ABCD = 2 × Area of ΔABC
= 2 × 18
= 36 cm2
APPEARS IN
संबंधित प्रश्न
Each side of a rhombus is 18 cm. If the distance between two parallel sides is 12 cm, find its area.
The length of the diagonals of a rhombus is in ratio 4 : 3. If its area is 384 cm2, find its side.
A thin metal iron-sheet is rhombus in shape, with each side 10 m. If one of its diagonals is 16 m, find the cost of painting both sides at the rate of ₹ 6 per m2. Also, find the distance between the opposite sides of this rhombus.
Find the area of a rhombus whose base is 14 cm and height is 9 cm.
Find the missing value.
| Diagonal (d1) | Diagonal (d2) | Area |
| 26 m | 468 sq.m |
The area of the rhombus with side 4 cm and height 3 cm is
The area of the rhombus is 128 sq.cm and the length of one diagonal is 32 cm. The length of the other diagonal is
The angle between the diagonals of a rhombus is
What is the area of the rhombus ABCD below if AC = 6 cm and BE = 4 cm?

Area of a quadrilateral ABCD is 20 cm2 and perpendiculars on BD from opposite vertices are 1 cm and 1.5 cm. The length of BD is ______.
