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A Student Says that He Had Applied a Force F = − K √ X on a Particle and the Particle Moved in Simple Harmonic Motion.

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प्रश्न

A student says that he had applied a force \[F = - k\sqrt{x}\] on a particle and the particle moved in simple harmonic motion. He refuses to tell whether k is a constant or not. Assume that he was worked only with positive x and no other force acted on the particle.

विकल्प

  • As x increases k increases.

  • As x increases k decreases.

  • As x increases k remains constant.

  • The motion cannot be simple harmonic.

MCQ
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उत्तर

As x increases k increases.


A body is said to be in simple harmonic motion only when,
   F = \[-\]kx                          ...(1)

where F is force,
           k is force constant, and
           x is displacement of the body from the mean position.

Given:
  F = -k\[\sqrt{x}\]...(2)

On comparing the equations (1) and (2), it can be said that in order to execute simple harmonic motion, k should be proportional to \[\sqrt{x}\] .

 Thus, as x increases k increases.

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अध्याय 12: Simple Harmonics Motion - MCQ [पृष्ठ २५०]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 12 Simple Harmonics Motion
MCQ | Q 1 | पृष्ठ २५०

वीडियो ट्यूटोरियलVIEW ALL [1]

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