हिंदी
कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान कक्षा ११

Motion of a ball bearing inside a smooth curved bowl, when released from a point slightly above the lower point is ______. simple harmonic motion. non-periodic motion. periodic motion.

Advertisements
Advertisements

प्रश्न

Motion of a ball bearing inside a smooth curved bowl, when released from a point slightly above the lower point is ______.

  1. simple harmonic motion.
  2. non-periodic motion.
  3. periodic motion.
  4. periodic but not S.H.M.
रिक्त स्थान भरें
टिप्पणी लिखिए
Advertisements

उत्तर

a and c

Explanation:

For small angular displacement, the situation is shown in the figure. Only one restoring force creates motion in a ball inside the bowl.


F = – mg sin θ

As θ is small, sin θ = θ

So, `ma = - mg x/R`

or a = `- (g/R)x`

⇒ a ∝ – x

So, the motion of the ball is S.H.M and periodic.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Oscillations - Exercises [पृष्ठ १००]

APPEARS IN

एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 14 Oscillations
Exercises | Q 14.13 | पृष्ठ १००

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

A particle executing simple harmonic motion comes to rest at the extreme positions. Is the resultant force on the particle zero at these positions according to Newton's first law?


A small creature moves with constant speed in a vertical circle on a bright day. Does its shadow formed by the sun on a horizontal plane move in a sample harmonic motion?


A particle executes simple harmonic motion Let P be a point near the mean position and Q be a point near an extreme. The speed of the particle at P is larger than the speed at Q. Still the particle crosses Pand Q equal number of times in a given time interval. Does it make you unhappy?


A block of known mass is suspended from a fixed support through a light spring. Can you find the time period of vertical oscillation only by measuring the extension of the spring when the block is in equilibrium?


Suppose a tunnel is dug along a diameter of the earth. A particle is dropped from a point, a distance h directly above the tunnel. The motion of the particle as seen from the earth is
(a) simple harmonic
(b) parabolic
(c) on a straight line
(d) periodic


A particle executes simple harmonic motion with an amplitude of 10 cm and time period 6 s. At t = 0 it is at position x = 5 cm going towards positive x-direction. Write the equation for the displacement x at time t. Find the magnitude of the acceleration of the particle at t = 4 s.


A pendulum clock giving correct time at a place where g = 9.800 m/s2 is taken to another place where it loses 24 seconds during 24 hours. Find the value of g at this new place.


A small block oscillates back and forth on a smooth concave surface of radius R in Figure. Find the time period of small oscillation.


A simple pendulum of length 1 feet suspended from the ceiling of an elevator takes π/3 seconds to complete one oscillation. Find the acceleration of the elevator.


A simple pendulum fixed in a car has a time period of 4 seconds when the car is moving uniformly on a horizontal road. When the accelerator is pressed, the time period changes to 3.99 seconds. Making an approximate analysis, find the acceleration of the car.


A closed circular wire hung on a nail in a wall undergoes small oscillations of amplitude 20 and time period 2 s. Find (a) the radius of the circular wire, (b) the speed of the particle farthest away from the point of suspension as it goes through its mean position, (c) the acceleration of this particle as it goes through its mean position and (d) the acceleration of this particle when it is at an extreme position. Take g = π2 m/s2.


A particle is subjected to two simple harmonic motions of same time period in the same direction. The amplitude of the first motion is 3.0 cm and that of the second is 4.0 cm. Find the resultant amplitude if the phase difference between the motions is (a) 0°, (b) 60°, (c) 90°.


A simple pendulum has a time period T1. When its point of suspension is moved vertically upwards according to as y = kt2, where y is the vertical distance covered and k = 1 ms−2, its time period becomes T2. Then, T `"T"_1^2/"T"_2^2` is (g = 10 ms−2)


Define the time period of simple harmonic motion.


Write short notes on two springs connected in series.


Write short notes on two springs connected in parallel.


Consider the Earth as a homogeneous sphere of radius R and a straight hole is bored in it through its centre. Show that a particle dropped into the hole will execute a simple harmonic motion such that its time period is

T = `2π sqrt("R"/"g")`


Consider a simple pendulum of length l = 0.9 m which is properly placed on a trolley rolling down on a inclined plane which is at θ = 45° with the horizontal. Assuming that the inclined plane is frictionless, calculate the time period of oscillation of the simple pendulum.


If x = `5 sin (pi t + pi/3) m` represents the motion of a particle executing simple harmonic motion, the amplitude and time period of motion, respectively, are ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×