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प्रश्न
A series LCR circuit is connected to a source having voltage v = vm sin ωt. Derive the expression for the instantaneous current I and its phase relationship to the applied voltage.
Obtain the condition for resonance to occur. Define ‘power factor’. State the conditions under which it is (i) maximum and (ii) minimum.
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उत्तर
v = vm sin ωt
Let the current in the circuit be led the applied voltage by an angleΦ.
`i= i_m sin(omegat +phi)`
The Kirchhoff’s voltage law gives`L ((di)/dt +Ri +q/C = v)`.
It is given that v = vm sin ωt (applied voltage)
`L(d^2q)/(dt^2) +R(dq)/(dt) +q/C = v_m sinomegat ...... (1)`
On solving the equation, we obtain
`q = q_m sin(omegat + theta)`
`(dp)/(dt) = q_momega cos(omegat +theta)`
`((d^2)q)/(dt^2) = -q_momega^2 sin(omegat +theta)`
On substituting these values in equation (1), we obtain
`q_momega[R cos(omegat +theta)+ (X_c -X_L)sin(omegat +theta)] = v_msinomegat`
`X_c = 1/(omegaC) X_c = omegaL`
`Z = sqrt(R^2 +(X_c - X_L)^2`
`q_momegaZ[R/Z cos(omegat+theta)+((X_c -X_L))/Z sin (omegat+theta)] = v_m sin omegat ........... (2)`
Let `cos phi = R/2` and `(X_c -X_L)/Z = sinphi`
This gives
`tan phi = (X_c - X_L)/R`
On substituting this in equation (2), we obtain
`q_momegaZcos (omegat +theta -phi) = v_msinomegat`
On comparing the two sides, we obtain
`V_m = q_momegaZ = i+mZ`
`i_m = q_momega`
and `(theta-phi) = -pi/2`
`I = (dp)/(dt ) =q_momega cos (omegat+theta)`
`=i_m cos(omegat+theta)`
Or
`i = i_m sin(omegat +theta)`
Where,`i_m = (v_m)/Z = (v_m)/(sqrt(R^2 +(X_c - X_L)^2)`
And
`phi = tan^-1((X_c -X_L)/R)`
The condition for resonance to occur
`i_m = v_m/sqrt(R^2 +(X_C - X_L)^2)`
For resonance to occur, the value of im has to be the maximum.
The value of im will be the maximum when
`X_c = X_L`
`1/(omega C) = omegaL`
`omega^2 = 1/(LC)`
`omega = 1/(sqrtLC)`
`2pif = 1/sqrt(LC)`
`f = 1/(02pisqrt(LC)`
Power factor = cos Φ

Where,`cosphi = R/Z = R/(sqrt(R^2 +(X_c- X_L)^2)`
(i) Conditions for maximum power factor (i.e., cos Φ = 1)
-
XC = XL
Or
-
R = 0
(ii) Conditions for minimum power factor
-
When the circuit is purely inductive
-
When the circuit is purely capacitive
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