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प्रश्न
A project schedule has the following characteristics
| Activity | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 9 | 5 - 6 | 5 - 7 | 6 - 8 | 7 - 8 | 8 - 10 | 9 - 10 |
| Time | 4 | 1 | 1 | 1 | 6 | 5 | 4 | 8 | 1 | 2 | 5 | 7 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
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उत्तर
E1 = 0
E2 = 0 + 4 = 4
E3 = 0 + 1 = 1
E4 = 4 + 1 = 5
E5 = 1 + 6 = 7
E6 = 7 + 4 = 11
E7 = 8 + 7 = 15
E8 = 15 + 2 = 7
E9 = 5 + 5 = 10
E10 = 17 + 5 = 22
L7 = 31
L10 = 22
L9 = 22 – 7 = 15
L8 = 22 – 5 = 17
L7 = 17 – 2 = 15
L6 = 17 – 1 = 16
L5 = (16 – 4) or (15 – 8)
whichever is minimum = 7
L4 = 15 – 5 = 10
L3 = (10 – 1) or (7 – 6)
whichever is minimum = 1
L2 = 10 – 1 = 9
L1 = 0
| Activity | Duration tij |
EST | EFT = EST + tij | LST = LFT – tij | LFT |
| 1 - 2 | 4 | 0 | 4 | 9 – 4 = 5 | 9 |
| 1 - 3 | 1 | 0 | 1 | 1 – 1 = 0 | 1 |
| 2 - 4 | 1 | 4 | 5 | 10 – 1 = 9 | 10 |
| 3 - 4 | 1 | 1 | 2 | 10 – 1 = 9 | 10 |
| 3 - 5 | 6 | 1 | 7 | 7 – 6 =1 | 7 |
| 4 - 9 | 5 | 5 | 10 | 15 – 5 =10 | 15 |
| 5 - 6 | 4 | 7 | 11 | 16 4 = 12 | 16 |
| 5 - 7 | 8 | 7 | 15 | 15 – 8 = 7 | 15 |
| 6 - 8 | 1 | 11 | 12 | 17 – 1 = 16 | 17 |
| 7 - 8 | 2 | 15 | 17 | 17 – 2 = 15 | 17 |
| 8 - 10 | 5 | 17 | 22 | 22 – 5 = 17 | 22 |
| 9 - 10 | 7 | 10 | 17 | 22 – 7 = 15 | 22 |
Since EFT and LFT is same on 1 - 3, 3 - 5, 5 - 7 and 7 - 8 and 8 - 10 the critical path is 1 - 3 - 5 - 7 - 8 - 10 and the duration is 22 time units.
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संबंधित प्रश्न
Construct the network for the project whose activities are given below.
| Activity | 0 - 1 | 1 - 2 | 1 - 3 | 2 - 4 | 2 - 5 | 3 - 4 | 3 - 6 | 4 - 7 | 5 - 7 | 6 - 7 |
| Duration (in week) | 3 | 8 | 12 | 6 | 3 | 3 | 8 | 5 | 3 | 8 |
Calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity. Determine the critical path and the project completion time.
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
| Jobs | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 | 4 - 6 | 5 - 6 |
| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
The following table use the activities in a construction projects and relevant information
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 4 - 5 |
| Duration (in days) |
22 | 27 | 12 | 14 | 6 | 12 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
The critical path of the following network is
In constructing the network which one of the following statements is false?
In a network while numbering the events which one of the following statements is false?
The objective of network analysis is to
In critical path analysis, the word CPM mean
Draw a network diagram for the following activities.
| Activity code | A | B | C | D | E | F | G | H | I | J | K |
| Predecessor activity | - | A | A | A | B | C | C | C, D | E, F | G, H | I, J |
The following table gives the characteristics of the project
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 3 - 4 | 3 - 5 | 4 - 6 | 5 - 6 | 6 - 7 |
| Duration (in days) |
5 | 10 | 3 | 4 | 6 | 6 | 5 | 5 |
Draw the network for the project, calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and find the critical path. Compute the project duration.
