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प्रश्न
One of the conditions for the activity (i, j) to lie on the critical path is
विकल्प
Ej – Ei = Lj – Li = tij
Ei – Ej = Lj – Li = tij
Ej – Ei = Li – Lj = tij
Ej – Ei = Lj – Li ≠ tij
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उत्तर
Ej – Ei = Lj – Li = tij
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संबंधित प्रश्न
Draw the event oriented network for the following data:
| Events | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
| Immediate Predecessors | - | 1 | 1 | 2, 3 | 3 | 4, 5 | 5, 6 |
Construct the network for the project whose activities are given below.
| Activity | 0 - 1 | 1 - 2 | 1 - 3 | 2 - 4 | 2 - 5 | 3 - 4 | 3 - 6 | 4 - 7 | 5 - 7 | 6 - 7 |
| Duration (in week) | 3 | 8 | 12 | 6 | 3 | 3 | 8 | 5 | 3 | 8 |
Calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity. Determine the critical path and the project completion time.
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| Activity | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 9 | 5 - 6 | 5 - 7 | 6 - 8 | 7 - 8 | 8 - 10 | 9 - 10 |
| Time | 4 | 1 | 1 | 1 | 6 | 5 | 4 | 8 | 1 | 2 | 5 | 7 |
Construct the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
Draw the network and calculate the earliest start time, earliest finish time, latest start time and latest finish time of each activity and determine the Critical path of the project and duration to complete the project.
| Jobs | 1 - 2 | 1 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 | 4 - 6 | 5 - 6 |
| Duration | 6 | 5 | 10 | 3 | 4 | 6 | 2 | 9 |
The following table gives the activities of a project and their duration in days
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 3 - 5 | 4 - 5 |
| Duration | 5 | 8 | 6 | 7 | 5 | 4 | 8 |
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The following table use the activities in a construction projects and relevant information
| Activity | 1 - 2 | 1 - 3 | 2 - 3 | 2 - 4 | 3 - 4 | 4 - 5 |
| Duration (in days) |
22 | 27 | 12 | 14 | 6 | 12 |
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