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A Non-monochromatic Light is Used in an Experiment on Photoelectric Effect. the Stopping Potential

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प्रश्न

A non-monochromatic light is used in an experiment on photoelectric effect. The stopping potential

विकल्प

  • is related to the mean wavelength

  •  is related to the longest wavelength

  • is related to the shortest wavelength

  • is not related to the wavelength

MCQ
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उत्तर

is related to the shortest wavelength

For photoelectric effect to be observed, wavelength of the incident light `(λ)` should be less than the threshold wavelength `(λ_0)` of the metal .

Einstein's photoelectric equation :

`eV_0 = (hc)/(λ_0) - varphi`

Here, V0 = stopping potential

`λ_0` = threshold wavelength

h = Planck's constant

`varphi` = work-function of metal
It is clear from the above equation that stopping potential is related to the shortest wavelength (threshold wavelength).

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 42: Photoelectric Effect and Wave-Particle Duality - MCQ [पृष्ठ २६४]

APPEARS IN

एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
अध्याय 42 Photoelectric Effect and Wave-Particle Duality
MCQ | Q 13 | पृष्ठ २६४

संबंधित प्रश्न

Plot a graph showing the variation of photoelectric current with collector plate potential at a given frequency but for two different intensities I1 and I2, where I2 > I1.


point out any two characteristic properties of photons on which Einstein’s photoelectric equation is based ?


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Using Einstein’s photoelectric equation shows how the cut-off voltage and threshold frequency for a given photosensitive material can be determined with the help of a suitable plot/graph.


The electric field at a point associated with a light wave is `E = (100  "Vm"^-1) sin [(3.0 xx 10^15 "s"^-1)t] sin [(6.0 xx 10^15 "s"^-1)t]`.If this light falls on a metal surface with a work function of 2.0 eV, what will be the maximum kinetic energy of the photoelectrons?

(Use h = 6.63 × 10-34J-s = 4.14 × 10-15 eV-s, c = 3 × 108 m/s and me = 9.1 × 10-31kg)


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Use Einstein’s photoelectric equation to show how from this graph, 
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Use Einstein's photoelectric equation to show how from this graph,
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Radiation of frequency 1015 Hz is incident on three photosensitive surfaces A, B and C. Following observations are recorded:

Surface A: no photoemission occurs

Surface B: photoemission occurs but the photoelectrons have zero kinetic energy.

Surface C: photo emission occurs and photoelectrons have some kinetic energy.
Using Einstein’s photo-electric equation, explain the three observations.


A photon of wavelength 663 nm is incident on a metal surface. The work function of the metal is 1.50 eV. The maximum kinetic energy of the emitted photoelectrons is ______.


Which observation could classical wave theory not explain?


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Einstein proposed that light energy is absorbed in discrete packets called what?


Which equation gives the energy of one photon?


Which is Einstein’s photoelectric equation?


What does \[\phi_0\] represent in Einstein’s photoelectric equation?


What does \[K_{\max}\] represent?


What condition must be met for photoelectric emission to occur?


How can maximum kinetic energy be written in terms of stopping potential \[V_0\]?


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