हिंदी

A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm

Advertisements
Advertisements

प्रश्न

A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?

योग
Advertisements

उत्तर

Given, charges for 10 sq cm advertisement = ₹ 300

∴ Charges for 1 sq cm advertisement = `(₹ 300)/(10  "sq cm") xx 1` sq cm = ₹ 30

In order to find out the amount the company has to pay for a half page advertisement, we will find the area of half page of magazine and then multiply it with the charges for 1 sq cm advertisement.

Now, area of 1 page of magazine

= 15 cm × 24 cm

= 360 cm2

∴ Area of a half page of magazine

= `("Area of"  1  "page of magazine")/2`

= `360/2`

= 180 cm2

So, charges for half page advertisement

= Area of half page of magazine × Charges for 1 sq cm advertisement

= 180 × 30

= ₹ 5400

Hence, the company has to pay ₹ 5400 for it.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Mensuration - Exercise [पृष्ठ १००]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 6
अध्याय 6 Mensuration
Exercise | Q 51. | पृष्ठ १००

वीडियो ट्यूटोरियलVIEW ALL [1]

संबंधित प्रश्न

In the below fig. ∠AOB = 90°, AC = BC, OA = 12 cm and OC = 6.5 cm. Find the area of
ΔAOB.


ABCD is a parallelogram in which BC is produced to E such that CE = BC. AE intersects
CD at F.
(i) Prove that ar (ΔADF) = ar (ΔECF)
(ii) If the area of ΔDFB = 3 cm2, find the area of ||gm ABCD.


In below fig., PSDA is a parallelogram in which PQ = QR = RS and AP || BQ || CR. Prove
that ar (Δ PQE) = ar (ΔCFD).


In the given figure, PQRS is a parallelogram. If X and Y are mid-points of PQ and SRrespectively and diagonal Q is joined. The ratio ar (||gm XQRY) : ar (ΔQSR) =


ABCD is a rectangle with O as any point in its interior. If ar (ΔAOD) = 3 cm2 and ar (ΔABOC) = 6 cm2, then area of rectangle ABCD is


Find the area of a rectangle whose length and breadth are 25 m and 16 cm.


Which has the smaller area - two five-rupee notes together or a hundred rupee notes?


The King was very happy with carpenters Cheggu and Anar. They had made a very big and beautiful bed for him. So as gifts the king wanted to give some land to Cheggu, and some gold to Anar. Cheggu was happy. He took 100 meters of wire and tried to make different rectangles.

He made a 10 m × 40 m rectangle. Its area was 400 square meters. So he next made a 30 m × 20 m rectangle.

  • What other rectangles can he make with 100 meters of wire? Discuss which of these rectangles will have the biggest area.

Find the area of the following figure by counting squares:


Find the area of the following figure by counting squares:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×