Advertisements
Advertisements
प्रश्न
A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?
Advertisements
उत्तर
Given, charges for 10 sq cm advertisement = ₹ 300
∴ Charges for 1 sq cm advertisement = `(₹ 300)/(10 "sq cm") xx 1` sq cm = ₹ 30
In order to find out the amount the company has to pay for a half page advertisement, we will find the area of half page of magazine and then multiply it with the charges for 1 sq cm advertisement.
Now, area of 1 page of magazine
= 15 cm × 24 cm
= 360 cm2
∴ Area of a half page of magazine
= `("Area of" 1 "page of magazine")/2`
= `360/2`
= 180 cm2
So, charges for half page advertisement
= Area of half page of magazine × Charges for 1 sq cm advertisement
= 180 × 30
= ₹ 5400
Hence, the company has to pay ₹ 5400 for it.
APPEARS IN
संबंधित प्रश्न
Let ABCD be a parallelogram of area 124 cm2. If E and F are the mid-points of sides AB and
CD respectively, then find the area of parallelogram AEFD.
D is the mid-point of side BC of ΔABC and E is the mid-point of BD. if O is the mid-point
of AE, prove that ar (ΔBOE) = `1/8` ar (Δ ABC).
In the given figure, find the area of ΔGEF.
A, B, C, D are mid-points of sides of parallelogram PQRS. If ar (PQRS) = 36 cm2, then ar (ABCD) =
ABCD is a trapezium with parallel sides AB =a and DC = b. If E and F are mid-points of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFEand EFCD is
What will happen to the area of a rectangle, if its length and breadth both are trebled?
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| ? | 15 cm | 60 cm | ? |
This stamp has an area of 4 square cm. Guess how many such stamps will cover this big rectangle.
Find the area of the following figure by counting squares:
Which unit is used to express area?
