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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

A galvanometer coil has a resistance of 12 Ω and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V? - Physics

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प्रश्न

A galvanometer coil has a resistance of 12 Ω and the metre shows full scale deflection for a current of 3 mA. How will you convert the metre into a voltmeter of range 0 to 18 V?

संख्यात्मक
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उत्तर

Resistance of the galvanometer coil, G = 12 Ω

Current for which there is full scale deflection, Ig = 3 mA = 3 × 10−3 A

Range of the voltmeter is 0, which needs to be converted to 18 V.

∴ V = 18 V

Let a resistor of resistance R be connected in series with the galvanometer to convert it into a voltmeter. This resistance is given as:

R = `"V"/"I"_"g" - "G"`

= `18/(3 xx 10^-3) - 12`

= 6000 − 12

= 5988 Ω

Hence, a resistor of resistance 5988 Ω is to be connected in series with the galvanometer.

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