हिंदी

Define the term ‘current sensitivity’ of a moving coil galvanometer.

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प्रश्न

Define the term ‘current sensitivity’ of a moving coil galvanometer.

परिभाषा
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उत्तर १

The current sensitivity of a galvanometer is defined as the deflection produced in the galvanometer when a unit current flows through it.  
Mathematically, it can be given by:

IS = `(NBA)/k`

Where k is the couple per unit twist.

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उत्तर २

Current sensitivity is defined as the deflection e per unit current.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2019-2020 (March) Delhi Set 2

वीडियो ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्न

  1. A circular coil of 30 turns and radius 8.0 cm carrying a current of 6.0 A is suspended vertically in a uniform horizontal magnetic field of magnitude 1.0 T. The field lines make an angle of 60° with the normal of the coil. Calculate the magnitude of the counter torque that must be applied to prevent the coil from turning.
  2. Would your answer change, if the circular coil in (a) were replaced by a planar coil of some irregular shape that encloses the same area? (All other particulars are also unaltered.)

The fraction of the total current passing through the galvanometer is ............ .

a) `S/(S+G)`

b) `G/(S+G)`

c) `(S+G)/G`

d) `(S+G)/S`


With the help of a neat and labelled diagram, explain the principle and working of a moving coil galvanometer ?


Define current sensitivity of a galvanometer.


Figure shows two circuits each having a galvanometer and a battery of 3V.

When the galvanometers in each arrangement do not show any deflection, obtain the ratio R1/R2.


Draw a labelled diagram of a moving coil galvanometer and explain its working. What is the function of radial magnetic field inside the coil?


Explain the significance of a radial magnetic field when a current-carrying coil is kept in it. 


An electric charge in uniform motion produces ______.

The current sensitivity of a galvanometer increase by 20%. If its resistance also increases by 25%, the voltage sensitivity will ______.


A moving coil galvanometer of resistance 55 Ω produces a full scale deflection for a current of 250 mA. How will you convert it into an ammeter with a range of 0 - 3A?


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