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प्रश्न
A cube of ice whose side is 4.0 cm is allowed to melt. The volume of water formed is found to be 58.24 cm3. Find the density of ice.
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उत्तर
Side of ice cube = l = 4 cm
Volume of ice cube = V = β = (4)3 = 64 cm3
Volume of water = V = 5824 cm3
Density of ice cube = ρi= ?
Density of water = ρw = 1 gem-3
By law of floatation:
Volume of ice cube x Density of ice=Volume of water x Density of water
64 x ρi = 58.24 x 1
`rho_"i" = 58.24/64`
`rho_"i" = 0.91` g cm-3
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