Advertisements
Advertisements
Question
A cube of ice whose side is 4.0 cm is allowed to melt. The volume of water formed is found to be 58.24 cm3. Find the density of ice.
Advertisements
Solution
Side of ice cube = l = 4 cm
Volume of ice cube = V = β = (4)3 = 64 cm3
Volume of water = V = 5824 cm3
Density of ice cube = ρi= ?
Density of water = ρw = 1 gem-3
By law of floatation:
Volume of ice cube x Density of ice=Volume of water x Density of water
64 x ρi = 58.24 x 1
`rho_"i" = 58.24/64`
`rho_"i" = 0.91` g cm-3
APPEARS IN
RELATED QUESTIONS
A body is held immersed in a liquid. (i) Name the two forces acting on the body and draw a diagram to show these forces. (ii) State how the magnitudes of two forces mentioned in part (i) determine whether the body will float or sink in liquid when it is released. (iii) What is the net force on the body if it (a) sinks and (b) floats?
A solid iron ball of mass 500 g is dropped in mercury contained in a beaker. (a) Will the ball float or sink? Give reasons. (b) What will be the apparent weight of the ball?
Why is the floating ice less submerged in brine than in water?
Why does a ship make of iron not sink in water, while an iron nail sinks in it?
A block of wood of volume 25 cm3 floats in water with 20 cm3 of its volume immersed in water.
Calculate:
(1) density of wood
(2) the weight of block of wood.
Explain the following:
A hydrometer is made heavy near the bottom.
Why do petroleum-based products float on the surface of the water?
Where do we use lactometers?
Differentiate positive & negative buoyant.
