Advertisements
Advertisements
Question
A cube of ice whose side is 4.0 cm is allowed to melt. The volume of water formed is found to be 58.24 cm3. Find the density of ice.
Advertisements
Solution
Side of ice cube = l = 4 cm
Volume of ice cube = V = β = (4)3 = 64 cm3
Volume of water = V = 5824 cm3
Density of ice cube = ρi= ?
Density of water = ρw = 1 gem-3
By law of floatation:
Volume of ice cube x Density of ice=Volume of water x Density of water
64 x ρi = 58.24 x 1
`rho_"i" = 58.24/64`
`rho_"i" = 0.91` g cm-3
APPEARS IN
RELATED QUESTIONS
A body is held immersed in a liquid. (i) Name the two forces acting on the body and draw a diagram to show these forces. (ii) State how the magnitudes of two forces mentioned in part (i) determine whether the body will float or sink in liquid when it is released. (iii) What is the net force on the body if it (a) sinks and (b) floats?
A solid iron ball of mass 500 g is dropped in mercury contained in a beaker. (a) Will the ball float or sink? Give reasons. (b) What will be the apparent weight of the ball?
A block of wood is so loaded that it just floats in water at room temperature. What change will occur in the state of floatation, if
(a) Some salt is added to water, (b) Water is heated?
Give reasons.
Why is the floating ice less submerged in brine than in water?
For a floating body, its weight W and upthrust FB on it are related as :
A test tube weighing 17 gf, floats in alcohol to the level P. When the test tube is made to float in water to the level P, 3 gf of the lead shots are added in it. find the R.D. of alcohol.
A test tube loaded with lead shots weighs 25 gf and floats upto the mark X in water. When the test tube is made to float in brine solution, it needs 5 gf more of lead shots to float upto level X. Find the relative density of brine solution.
If you put one ice cube in a glass of water and another in a glass of alcohol, what would you observe? Explain your observations.
Hydrometer is based on the principle of ______.
