Advertisements
Advertisements
प्रश्न
A cell of e.m.f 2.0 V and internal resistance 1Ω is connected to the resistors of 3Ω and 6Ω in series. Calculate:
(i) the current drawn from the cell,
(ii) the p.d. across each resistor,
(iii) the terminal voltage of the cell and
(iv) the voltage drop.
Advertisements
उत्तर
Total resistance of the circuit R = 1 + 3 + 6 = 10 Ω
(i) The current drawn from the cell = `"E"/"R" = 2.0/10 = 0.2` A
(ii) The p.d. across 3 Ω resistor V1 = IR1 = 0.2 × 3 = 0.6V
The p.d. across 6 Ω resistor V2 = IR2 = 0.2 × 6 = 1.2 V
(iii) The terminal voltage of the cell V = V1 + V2
= 0.6 + 1.2 = 1.8 V
(iv) The voltage drop = E - V = 2.0 - 1.8 = 0.2 V
संबंधित प्रश्न
Name a device that helps to maintain a potential difference across a conductor.
Which of the following statements correctly defines a volt?
(a) a volt is a joule per ampere.
(b) a volt is a joule per coulomb.
What is the ratio of potential difference and current known as?
Keeping the potential difference constant, the resistance of a circuit is doubled. The current will become:
A current of 200 mA flows through a 4 kΩ resistor. What is the p.d. across the resistor?
Three electric cells of potential difference 1.5 V each have been connected as a battery. The potential differences of the battery will be ____________ V.
Three resistors are connected to a 6 V battery as shown in the figure given below:
Calculate:
(i) the equivalent resistance of the circuit.
(ii) total current in the circuit.
(iii) potential difference across the 7.2 Ω resistor.
A current of 1 ampere flows in a series circuit containing an electric lamp and a conductor of 5 Ω when connected to a 10 V battery. Calculate the resistance of the electric lamp.
Now if a resistance of 10 Ω is connected in parallel with this series combination, what change (if any) in current flowing through 5 Ω conductor and potential difference across the lamp will take place? Give reason.
Assertion (A): Charges flow from higher potential to lower potential.
Reason (R): Current flows mainly due to the flow of electrons.
Twenty-seven drops of the same size are charged at 220 V each. They combine to form a bigger drop. Calculate the potential of the bigger drop.
