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A Ball is Thrown at a Speed of 40 M/S at an Angle of 60° with the Horizontal. Find The Range of the Ball. Take G = 10 M/S2. - Physics

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प्रश्न

A ball is thrown at a speed of 40 m/s at an angle of 60° with the horizontal. Find   the range of the ball. Take g = 10 m/s2

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उत्तर

Given:
Initial speed of the ball, u = 40 m/s
Angle of projection of the ball with the horizontal, α = 60°
Also,
a = g = 10 m/s2

Horizontal range of the ball: 

\[R = \frac{u^2 \sin2\alpha}{g}\]

\[= \frac{{40}^2 \sin\left( 2 \times 60^\circ\right)}{10} = 80\sqrt{3} \text{ m } \]

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अध्याय 3: Rest and Motion: Kinematics - Exercise [पृष्ठ ५२]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 3 Rest and Motion: Kinematics
Exercise | Q 33.2 | पृष्ठ ५२

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