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A Swimmer Wishes to Cross a 500 M Wide River Flowing at 5 Km/H. His Speed with Respect to Water is 3 Km/H. If He Heads in Direction Making an Angle θ with Flow, Find Time He Takes to Cross the River. - Physics

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प्रश्न

A swimmer wishes to cross a 500 m wide river flowing at 5 km/h. His speed with respect to water is 3 km/h. If he heads in a direction making an angle θ with the flow, find the time he takes to cross the river.

योग
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उत्तर

Given:
Width of the river = 500 m
Rate of flow of the river = 5 km/h
Swimmer's speed with respect to water = 3 km/h
As per the question, the swimmer heads in a direction making an angle θ with the flow.
We know that the vertical component of velocity 3 sin θ takes him to the opposite side of the river.
Distance to be travelled = 0.5 km
Vertical component of velocity = 3 sin θ km/h
Thus, we have:

\[\text{ Time }= \frac{\text{ Distance } }{\text{ Velocity }} = \frac{0 . 5}{3\sin\theta} h = \frac{500 \times 6}{5\sin\theta} = \frac{600}{\sin\theta} s\]

∴ Required time =\[\frac{10 \text{ minutes } }{\sin\theta}\]

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अध्याय 3: Rest and Motion: Kinematics - Exercise [पृष्ठ ५४]

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एचसी वर्मा Concepts of Physics Vol. 1 [English] Class 11 and 12
अध्याय 3 Rest and Motion: Kinematics
Exercise | Q 47.1 | पृष्ठ ५४

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