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∫ 1 X √ 4 − 9 ( Log X ) 2 D X - Mathematics

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प्रश्न

\[\int\frac{1}{x\sqrt{4 - 9 \left( \log x \right)^2}} dx\]
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उत्तर

\[\int\frac{dx}{x\sqrt{4 - 9 \left( \log x \right)^2}}\]
` \text{ let log x }= t `
\[ \Rightarrow \frac{1}{x} dx = dt\]
\[Now, \int\frac{dx}{x\sqrt{4 - 9 \left( \log x \right)^2}}\]
\[ = \int\frac{dt}{\sqrt{4 - 9 t^2}}\]
\[ = \int\frac{dt}{\sqrt{2^2 - \left( 3t \right)^2}}\]
\[ = \frac{1}{3} \text{ sin }^{- 1} \left( \frac{3t}{2} \right) + C\]
\[ = \frac{1}{3} \text{  sin }^{- 1} \left( \frac{3 \log x}{2} \right) + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.18 [पृष्ठ ९९]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.18 | Q 7 | पृष्ठ ९९

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