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प्रश्न

\[\int\sqrt{1 + e^x} .  e^x dx\]
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उत्तर

\[\int\sqrt{1 + e^x} \cdot e^x dx\]

\[\text{Let 1 }+ e^x = t\]

\[ \Rightarrow e^x = \frac{dt}{dx}\]

\[ \Rightarrow e^x dx = dt\]

\[Now, \int\sqrt{1 + e^x} \cdot e^x dx\]

\[ = \int\sqrt{t} \cdot dt\]

\[ = \frac{t^\frac{1}{2} + 1}{\frac{1}{2} + 1} + C\]

\[ = \frac{2}{3} t^\frac{3}{2} + C\]

\[ = \frac{2}{3} \left( 1 + e^x \right)^\frac{3}{2} + C\]

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अध्याय 19: Indefinite Integrals - Exercise 19.09 [पृष्ठ ५७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
Exercise 19.09 | Q 4 | पृष्ठ ५७

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