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Karnataka Board PUCPUC Science 2nd PUC Class 12

PUC Science 2nd PUC Class 12 - Karnataka Board PUC Question Bank Solutions for Mathematics

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Mathematics
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Solve the following initial value problem:-

\[y' + y = e^x , y\left( 0 \right) = \frac{1}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-
\[x\frac{dy}{dx} - y = \log x, y\left( 1 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

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Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y = e^{- 2x} \sin x, y\left( 0 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[x\frac{dy}{dx} - y = \left( x + 1 \right) e^{- x} , y\left( 1 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\left( 1 + y^2 \right) dx + \left( x - e^{- \tan^{- 1} y} \right) dx = 0, y\left( 0 \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + y \tan x = 2x + x^2 \tan x, y\left( 0 \right) = 1\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:
\[x\frac{dy}{dx} + y = x \cos x + \sin x, y\left( \frac{\pi}{2} \right) = 1\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:
\[\frac{dy}{dx} + y \cot x = 4x\text{ cosec }x, y\left( \frac{\pi}{2} \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + 2y \tan x = \sin x; y = 0\text{ when }x = \frac{\pi}{3}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} - 3y \cot x = \sin 2x; y = 2\text{ when }x = \frac{\pi}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[\frac{dy}{dx} + y\cot x = 2\cos x, y\left( \frac{\pi}{2} \right) = 0\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-

\[dy = \cos x\left( 2 - y\text{ cosec }x \right)dx\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

Solve the following initial value problem:-
\[\tan x\left( \frac{dy}{dx} \right) = 2x\tan x + x^2 - y; \tan x \neq 0\] given that y = 0 when \[x = \frac{\pi}{2}\]

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The surface area of a balloon being inflated, changes at a rate proportional to time t. If initially its radius is 1 unit and after 3 seconds it is 2 units, find the radius after time t.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

A population grows at the rate of 5% per year. How long does it take for the population to double?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The rate of growth of a population is proportional to the number present. If the population of a city doubled in the past 25 years, and the present population is 100000, when will the city have a population of 500000?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

In a culture, the bacteria count is 100000. The number is increased by 10% in 2 hours. In how many hours will the count reach 200000, if the rate of growth of bacteria is proportional to the number present?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

If the interest is compounded continuously at 6% per annum, how much worth Rs 1000 will be after 10 years? How long will it take to double Rs 1000?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The rate of increase in the number of bacteria in a certain bacteria culture is proportional to the number present. Given the number triples in 5 hrs, find how many bacteria will be present after 10 hours. Also find the time necessary for the number of bacteria to be 10 times the number of initial present.

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined

The population of a city increases at a rate proportional to the number of inhabitants present at any time t. If the population of the city was 200000 in 1990 and 250000 in 2000, what will be the population in 2010?

[9] Differential Equations
Chapter: [9] Differential Equations
Concept: undefined >> undefined
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