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Solve for x:
`tan^-1 [(x-1),(x-2)] + tan^-1 [(x+1),(x+2)] = x/4`
Concept: undefined >> undefined
Evaluate: tan `[ 2 tan^-1 (1)/(2) – cot^-1 3]`
Concept: undefined >> undefined
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Solve for x:
5tan–1x + 3cot–1x = 2π
Concept: undefined >> undefined
Find the value of `tan^-1(x/y) + tan^-1((y - x)/(y + x))`
Concept: undefined >> undefined
The binary operation *: R x R → R is defined as a *b = 2a + b Find (2 * 3)*4
Concept: undefined >> undefined
A relation R on (1, 2, 3) is given by R = {(1, 1), (2, 2), (1, 2), (3, 3), (2, 3)}. Then the relation R is ______.
Concept: undefined >> undefined
Let L be a set of all straight lines in a plane. The relation R on L defined as 'perpendicular to' is ______.
Concept: undefined >> undefined
Statement 1: The intersection of two equivalence relations is always an equivalence relation.
Statement 2: The Union of two equivalence relations is always an equivalence relation.
Which one of the following is correct?
Concept: undefined >> undefined
If a relation R on the set {a, b, c} defined by R = {(b, b)}, then classify the relation.
Concept: undefined >> undefined
If cos-1 x + cos -1 y + cos -1 z = π , prove that x2 + y2 + z2 + 2xyz = 1.
Concept: undefined >> undefined
If y = `(x sin^-1 x)/sqrt(1 -x^2)`, prove that: `(1 - x^2)dy/dx = x + y/x`
Concept: undefined >> undefined
If `tan^-1 ((x - 1)/(x + 1)) + tan^-1 ((2x - 1)/(2x + 1)) = tan^-1 (23/36)` = then prove that 24x2 – 23x – 12 = 0
Concept: undefined >> undefined
The value of cosec `[sin^-1((-1)/2)] - sec[cos^-1((-1)/2)]` is equal to ______.
Concept: undefined >> undefined
Solve for x: `sin^-1(x/2) + cos^-1x = π/6`
Concept: undefined >> undefined
If sin–1x + sin–1y + sin–1z = π, show that `x^2 - y^2 - z^2 + 2yzsqrt(1 - x^2) = 0`
Concept: undefined >> undefined
Solve:
sin–1 (x) + sin–1 (1 – x) = cos–1 x
Concept: undefined >> undefined
If the function `f(x) = sqrt(2x - 3)` is invertible then find its inverse. Hence prove that `(fof^(-1))(x) = x`
Concept: undefined >> undefined
Let \[f\left(x\right) = x^3\] be a function with domain {0, 1, 2, 3}. Then domain of \[f^{-1}\] is ______.
Concept: undefined >> undefined
Let A = R – {2} and B = R – {1}. If f: A `→` B is a function defined by f(x) = `(x - 1)/(x - 2)` then show that f is a one-one and an onto function.
Concept: undefined >> undefined
Which one of the following graphs is a function of x?
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| Graph A | Graph B |
Concept: undefined >> undefined


