(English Medium) ICSE Class 10 - CISCE Question Bank Solutions

What do you understand by redox reactions? Explain oxidation and reduction in terms of loss or gain of electrons.

State the following is a reduction reaction or oxidation reaction.

\[\ce{Pb -> Pb^2+ + 2e-}\]

State the following is a reduction reaction or oxidation reaction.

\[\ce{Fe^2+ - e- -> Fe^3+}\]

State the following is a reduction reaction or oxidation reaction.

\[\ce{A^3+ + e- -> A^2+}\]

State the following is a reduction reaction or oxidation reaction.

\[\ce{Cu -> Cu^2+}\]

Answer the questions below relating your answers only to salts in the following list: Sodium chloride, anhydrous calcium chloride, copper sulphate-5-water?

1. What name is given to the water in the compound copper sulphate-5-water?
2. If copper sulphate-5-water is heated, anhydrous coppersulphate is formed. What is its colour?
3. By what means, other than healing, could you dehydrate copper sulphate-5-water and obtain anhydrous coppersulphate?
4. Which one of the salts in the given list is deliquescent?

Name the probable cation present based on the following observation:

White precipitate insoluble in NH₄OH but soluble in NaOH.

Name : 

a coloured metallic oxide which dissolves in alkalis to yield colourless solutions.

Colour of an aqueous solution of copper sulphate is ______.

Colour of the precipitate formed on adding NaOH solution to iron (II) sulphate solution is ______.

A metal which produces hydrogen on reacting with alkali as well as with acid.

Explain Why?

"When stating the volume of a gas, the pressure and temperature should also be given."

What do you understand by redox reactions?

Potassium (at No.19) and chlorine (at No.17) react to form a compound. Explain the formation of the compound on the basis of oxidation.

Potassium (at No.19) and chlorine (at No.17) react to form a compound. Explain the formation of the compound on the basis of reduction.

Potassium (at No.19) and chlorine (at No.17) react to form a compound. Explain the formation of the compound on the basis of oxidizing agent.

Potassium (at No.19) and chlorine (at No.17) react to form a compound. Explain the formation of the compound on the basis of reducing agent.

Complete the following blank in the equation as indicated.

\[\ce{CaH2_{(s)} + 2H2O_{( aq)}-> Ca(OH)2_{(s)} + 2H2_{(g)}}\]

Moles: 1 mole + ______ `→` ______ + ______

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate mass of MnO₂ used.

\[\ce{MnO2 + 4HCl -> MnCl2 + 2H2O + Cl2}\]

0.02 moles of pure MnO₂ is heated strongly with conc. HCl. Calculate moles of salt formed.