English Medium Class 9 - CBSE Question Bank Solutions

If x + \[\frac{1}{x}\] = then find the value of \[x^2 + \frac{1}{x^2}\].

If \[x + \frac{1}{x} = 3\]  then find the value of \[x^6 + \frac{1}{x^6}\].

If \[x - \frac{1}{x} = \frac{1}{2}\],then write the value of \[4 x^2 + \frac{4}{x^2}\]

If \[a^2 + \frac{1}{a^2} = 102\] , find the value of \[a - \frac{1}{a}\].

If a + b + c = 0, then write the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\]

Mark the correct alternative in each of the following:

If \[x + \frac{1}{x} = 5\] then \[x^2 + \frac{1}{x^2} = \]

If \[x + \frac{1}{x} = 2\], then \[x^3 + \frac{1}{x^3} =\]

If \[x + \frac{1}{x}\] 4, then \[x^4 + \frac{1}{x^4} =\]

If \[x + \frac{1}{x} = 3\] then \[x^6 + \frac{1}{x^6}\] = 

If \[x^2 + \frac{1}{x^2} = 102\], then \[x - \frac{1}{x}\] = 

If \[x^3 + \frac{1}{x^3} = 110\], then \[x + \frac{1}{x} =\]

If \[x^3 - \frac{1}{x^3} = 14\],then \[x - \frac{1}{x} =\]

If a + b + c = 9 and ab + bc + ca = 23, then a² + b² + c² =

(a − b)³ + (b − c)³ + (c − a)³ =

If \[\frac{a}{b} + \frac{b}{a} = - 1\] then a³ − b³ =

If a − b = −8 and ab  = −12, then a³ − b³ =