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Commerce (English Medium) Class 12 - CBSE Question Bank Solutions for Mathematics

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Consider f: R+ → [–5, ∞) given by f(x) = 9x2 + 6x – 5. Show that f is invertible with `f^(-1)(y) = ((sqrt(y + 6) - 1)/3)`.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f: X → Y be an invertible function. Show that f has unique inverse. (Hint: suppose g1 and g2 are two inverses of f. Then for all y ∈ Y, fog1(y) = IY(y) = fog2(y). Use one-one ness of f).

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

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Consider f: {1, 2, 3} → {a, b, c} given by f(1) = a, f(2) = b and f(3) = c. Find f−1 and show that (f−1)−1 = f.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f: X → Y be an invertible function. Show that the inverse of f−1 is f, i.e., (f−1)−1 = f.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f: R → R be given by `f(x) = (3 - x^3)^(1/3)`, then fof(x) is ______.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let `f: R - {-4/3} → R` be a function defined as `f(x) = (4x)/(3x + 4)`. The inverse of f is map g: Range `f → R - {-4/3}` given by

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let f: W → W be defined as f(n) = n − 1, if is odd and f(n) = n + 1, if n is even. Show that f is invertible. Find the inverse of f. Here, W is the set of all whole numbers.

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

If f: R → R is defined by f(x) = x2 − 3x + 2, find f(f(x)).

[1] Relations and Functions
Chapter: [1] Relations and Functions
Concept: undefined >> undefined

Let A be a nonsingular square matrix of order 3 × 3. Then |adj A| is equal to ______.

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

x + 2y = 2

2x + 3y = 3

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

2x − y = 5

x + y = 4

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

x + 3y = 5

2x + 6y = 8

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

x + y + z = 1

2x + 3y + 2z = 2

ax + ay + 2az = 4

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

3x − y − 2z = 2

2y − z = −1

3x − 5y = 3

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Examine the consistency of the system of equations.

5x − y + 4z = 5

2x + 3y + 5z = 2

5x − 2y + 6z = −1

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the system of linear equations using the matrix method.

5x + 2y = 4

7x + 3y = 5

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the system of linear equations using the matrix method.

2x – y = –2

3x + 4y = 3

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the system of linear equations using the matrix method.

4x – 3y = 3

3x – 5y = 7

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the system of linear equations using the matrix method.

5x + 2y = 3

3x + 2y = 5

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined

Solve the system of linear equations using the matrix method.

2x + y + z = 1

x – 2y – z = `3/2`

3y – 5z = 9

[4] Determinants
Chapter: [4] Determinants
Concept: undefined >> undefined
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