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Science (English Medium) Class 11 - CBSE Question Bank Solutions

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Prove the following identites

sec4x - sec2x = tan4x + tan2x

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\sin^6 x + \cos^6 x = 1 - 3 \sin^2 x \cos^2 x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

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Prove the following identities
\[\left( cosec x - \sin x \right) \left( \sec x - \cos x \right) \left( \tan x + \cot x \right) = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities 
\[cosec x \left( \sec x - 1 \right) - \cot x \left( 1 - \cos x \right) = \tan x - \sin x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{1 - \sin x \cos x}{\cos x \left( \sec x - cosec x \right)} \cdot \frac{\sin^2 x - \cos^2 x}{\sin^3 x + \cos^3 x} = \sin x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identitie

\[\frac{\tan x}{1 - \cot x} + \frac{\cot x}{1 - \tan x} = \left( \sec x cossec x + 1 \right)\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{\sin^3 x + \cos^3 x}{\sin x + \cos x} + \frac{\sin^3 x - \cos^3 x}{\sin x - \cos x} = 2\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\left( \sec x \sec y + \tan x \tan y \right)^2 - \left( \sec x \tan y + \tan x \sec y \right)^2 = 1\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\frac{\cos x}{1 - \sin x} = \frac{1 + \cos x + \sin x}{1 + \cos x - \sin x}\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities

\[\frac{\tan^3 x}{1 + \tan^2 x} + \frac{\cot^3 x}{1 + \cot^2 x} = \frac{1 - 2 \sin^2 x \cos^2 x}{\sin x \cos x}\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[1 - \frac{\sin^2 x}{1 + \cot x} - \frac{\cos^2 x}{1 + \tan x} = \sin x \cos x\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities

\[\left( \frac{1}{\sec^2 x - \cos^2 x} + \frac{1}{{cosec}^2 x - \sin^2 x} \right) \sin^2 x \cos^2 x = \frac{1 - \sin^2 x \cos^2 x}{2 + \sin^2 x \cos^2 x}\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities
\[\left( 1 + \tan \alpha \tan \beta \right)^2 + \left( \tan \alpha - \tan \beta \right)^2 = \sec^2 \alpha \sec^2 \beta\]

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities:

\[\frac{\left( 1 + \cot x + \tan x \right) \left( \sin x - \cos x \right)}{\sec^3 x - {cosec}^3 x} = \sin^2 x \cos^2 x\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities 

\[\frac{2 \sin x \cos x - \cos x}{1 - \sin x + \sin^2 x - \cos^2 x} = \cot x\]

 

[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

Prove the following identities

\[\cos x \left( \tan x + 2 \right) \left( 2 \tan x + 1 \right) = 2 \sec x + 5 \sin x\]
[3] Trigonometric Functions
Chapter: [3] Trigonometric Functions
Concept: undefined >> undefined

If \[X = \left\{ 8^n - 7n - 1: n \in N \right\} \text{ and } Y = \left\{ 49\left( n - 1 \right): n \in N \right\}\] \[X \subseteq Y .\]

[1] Sets
Chapter: [1] Sets
Concept: undefined >> undefined

Define a function as a set of ordered pairs.

 
[2] Relations and Functions
Chapter: [2] Relations and Functions
Concept: undefined >> undefined

If U = {2, 3, 5, 7, 9} is the universal set and A = {3, 7}, B = {2, 5, 7, 9}, then prove that: 

\[\left( A \cup B \right)' = A' \cap B'\] 

[1] Sets
Chapter: [1] Sets
Concept: undefined >> undefined

If U = {2, 3, 5, 7, 9} is the universal set and A = {3, 7}, B = {2, 5, 7, 9}, then prove that:

\[\left( A \cap B \right)' = A'B' .\]

 

[1] Sets
Chapter: [1] Sets
Concept: undefined >> undefined
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