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Science (English Medium) Class 11 - CBSE Question Bank Solutions

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Conjugate acid of a weak base is always stronger. What will be the decreasing order of basic strength of the following conjugate bases?

\[\ce{OH-, RO-, CH3COO-, Cl-}\]

[6] Equilibrium
Chapter: [6] Equilibrium
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\[\ce{pH}\] of 0.08 mol dm–3 \[\ce{HOCl}\] solution is 2.85. Calculate its ionisation constant

[6] Equilibrium
Chapter: [6] Equilibrium
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Assertion (A): Aqueous solution of ammonium carbonate is basic.

Reason (R): Acidic/basic nature of a salt solution of a salt of weak acid and weak base depends on Ka and Kb value of the acid and the base forming it.

[6] Equilibrium
Chapter: [6] Equilibrium
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For an electrophilic substitution reaction, the presence of a halogen atom in the benzene ring:

(i) deactivates the ring by inductive effect

(ii) deactivates the ring by resonance

(iii) increases the charge density at ortho and para position relative to meta position by resonance

(iv) directs the incoming electrophile to meta position by increasing the charge density relative to ortho and para position.

[9] Hydrocarbons
Chapter: [9] Hydrocarbons
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In an electrophilic substitution reaction of nitrobenzene, the presence of nitro group:

(i) Deactivates the ring by inductive effect.

(ii) Activates the ring by inductive effect.

(iii) Decreases the charge density at ortho and para position of the ring relative to meta position by resonance.

(iv) Increases the charge density at meta position relative to the ortho and para positions of the ring by resonance.

[9] Hydrocarbons
Chapter: [9] Hydrocarbons
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Why do alkenes prefer to undergo electrophilic addition reaction while arenes prefer electrophilic substitution reactions? Explain.

[9] Hydrocarbons
Chapter: [9] Hydrocarbons
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Why does presence of a nitro group make the benzene ring less reactive in comparison to the unsubstituted benzene ring. Explain.

[9] Hydrocarbons
Chapter: [9] Hydrocarbons
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Assertion (A): Nitration of benzene with nitric acid requires the use of concentrated sulphuric acid.

Reason (R): The mixture of concentrated sulphuric acid and concentrated nitric acid produces the electrophile, \[\ce{NO^{+}2}\].

[9] Hydrocarbons
Chapter: [9] Hydrocarbons
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Use molecular orbital theory to explain why the Be2 molecule does not exist.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Differentiate between the principle of estimation of nitrogen in an organic compound by Dumas method.

[8] Organic Chemistry - Some Basic Principles and Techniques
Chapter: [8] Organic Chemistry - Some Basic Principles and Techniques
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Differentiate between the principle of estimation of nitrogen in an organic compound by Kjeldahl’s method.

[8] Organic Chemistry - Some Basic Principles and Techniques
Chapter: [8] Organic Chemistry - Some Basic Principles and Techniques
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A sample of 0.50 g of an organic compound was treated according to Kjeldahl’s method. The ammonia evolved was absorbed in 50 mL of 0.5 M H2SO4. The residual acid required 60 mL of 0.5 M solution of NaOH for neutralisation. Find the percentage composition of nitrogen in the compound.

[8] Organic Chemistry - Some Basic Principles and Techniques
Chapter: [8] Organic Chemistry - Some Basic Principles and Techniques
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The first ionization constant of H2­­S is 9.1 × 10–8. Calculate the concentration of HSion in its 0.1 M solution. How will this concentration be affected if the solution is 0.1 M in HCl also? If the second dissociation constant of H2S is 1.2 × 10–13, calculate the concentration of S2– under both conditions.

[6] Equilibrium
Chapter: [6] Equilibrium
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Stable form of C may be represented by the formula:

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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The molecular formula of the compound formed from \[\ce{B}\] and \[\ce{C}\] will be ______.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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The electronic configuration of the outer most shell of the most electronegative element is ______.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Amongst the following elements whose electronic configurations are given below, the one having the highest ionisation enthalpy is ______.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Dimagnetic species are those which contain no unpaired electrons. Which among the following are dimagnetic?

(i) \[\ce{N2}\]

(ii) \[\ce{N^{2-}2}\]

(iii) \[\ce{O2}\] 

(iv) \[\ce{O^{2-}2}\]

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Explain the shape of \[\ce{BrF5}\].

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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Explain why \[\ce{PCl5}\] is trigonal bipyramidal whereas \[\ce{IF5}\] is square pyramidal.

[4] Chemical Bonding and Molecular Structure
Chapter: [4] Chemical Bonding and Molecular Structure
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