Science (English Medium) Class 12 - CBSE Important Questions for Mathematics

Solve the following for x:

`sin^(-1)(1-x)-2sin^-1 x=pi/2`

Show that:

`2 sin^-1 (3/5)-tan^-1 (17/31)=pi/4`

if `sin(sin^(-1)  1/5 + cos^(-1) x)  = 1` then find the value of x

Solve the following equation for x:  `cos (tan^(-1) x) = sin (cot^(-1)  3/4)`

For the principal value, evaluate of the following:

`cos^-1  1/2 + 2 sin^-1 (1/2)`

Find the value of x, if tan `[sec^(-1) (1/x) ] = sin ( tan^(-1) 2) , x > 0 `.

If tan^-1 x - cot^-1 x = tan^-1 `(1/sqrt(3)),`x> 0 then find the value of x and hence find the value of sec^-1 `(2/x)`.

Find: ∫ sin x · log cos x dx

Solve for x : `tan^-1 ((2-"x")/(2+"x")) = (1)/(2)tan^-1  ("x")/(2), "x">0.`

Assertion (A): The domain of the function sec^–12x is `(-∞, - 1/2] ∪ pi/2, ∞)`

Reason (R): sec^–1(–2) = `- pi/4`

Find the value of `sin^-1 [sin((13π)/7)]`

Draw the graph of the principal branch of the function f(x) = cos^–1 x.

Find the value of `tan^-1 [2 cos (2 sin^-1  1/2)] + tan^-1 1`.

Find the value of `sin^-1(cos((33π)/5))`.

A school wants to award its students for the values of Honesty, Regularity and Hard work with a total cash award of Rs 6,000. Three times the award money for Hard work added to that given for honesty amounts to Rs 11,000. The award money given for Honesty and Hard work together is double the one given for Regularity. Represent the above situation algebraically and find the award money for each value, using matrix method. Apart from these values, namely, Honesty, Regularity and Hard work, suggest one more value which the school must include for awards.

Use elementary column operation C₂ → C₂ + 2C₁ in the following matrix equation :

`[[2,1],[2,0]] = [[3,1],[2,0]] [[1,0],[-1,1]]`

A trust invested some money in two type of bonds. The first bond pays 10% interest and second bond pays 12% interest. The trust received Rs 2,800 as interest. However, if trust had interchanged money in bonds, they would have got Rs 100 less as interest. Using matrix method, find the amount invested by the trust. Interest received on this amount will be given to Helpage India as donation. Which value is reflected in this question?

If A =  `([cos alpha, sin alpha],[-sinalpha, cos alpha])` , find α satisfying 0 < α < `pi/r`when `A+A^T=sqrt2I_2` where A^T is transpose of A.

If A =  `([cos alpha, sin alpha],[-sinalpha, cos alpha])` , find α satisfying 0 < α < `pi/r`when `A+A^T=sqrt2I_2` where A^T is transpose of A.

If `A=[[2,3],[5,-2]]` then write A^-1