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Evaluate :
`∫(x+2)/sqrt(x^2+5x+6)dx`
Concept: Methods of Integration: Integration by Substitution
Evaluate : `int_2^3 3^x dx`
Concept: Integrals of Some Particular Functions
Find `int dx/(x^2 + 4x + 8)`
Concept: Integration Using Trigonometric Identities
Evaluate `int_0^(3/2) |x sin pix|dx`
Concept: Integration Using Trigonometric Identities
Evaluate `int (cos 2x + 2sin^2x)/(cos^2x) dx`
Concept: Some Properties of Indefinite Integral
Find `int (2cos x)/((1-sinx)(1+sin^2 x)) dx`
Concept: Methods of Integration: Integration Using Partial Fractions
Evaluate `int_0^(pi/4) (sinx + cosx)/(16 + 9sin2x) dx`
Concept: Evaluation of Definite Integrals by Substitution
Evaluate: `int_0^(pi/4) (dx)/(1 + tanx)`
Concept: Methods of Integration: Integration by Parts
Find: `int (dx)/(x^2 - 6x + 13)`
Concept: Integrals of Some Particular Functions
Evaluate: `int_0^(2π) (1)/(1 + e^(sin x)`dx
Concept: Properties of Definite Integrals
Anti-derivative of `(tanx - 1)/(tanx + 1)` with respect to x is ______.
Concept: Integration as an Inverse Process of Differentiation
Evaluate `int_(logsqrt(2))^(logsqrt(3)) 1/((e^x + e^-x)(e^x - e^-x)) dx`.
Concept: Methods of Integration: Integration by Substitution
`int secx/(secx - tanx)dx` equals ______.
Concept: Methods of Integration: Integration by Substitution
Assertion (A): `int_2^8 sqrt(10 - x)/(sqrt(x) + sqrt(10 - x))dx` = 3.
Reason (R): `int_a^b f(x) dx = int_a^b f(a + b - x) dx`.
Concept: Properties of Definite Integrals
Evaluate: `int_0^(π/2) sin 2x tan^-1 (sin x) dx`.
Concept: Evaluation of Definite Integrals by Substitution
Using integration find the area of the region {(x, y) : x2+y2⩽ 2ax, y2⩾ ax, x, y ⩾ 0}.
Concept: Area Under Simple Curves
Using integration find the area of the triangle formed by positive x-axis and tangent and normal of the circle
`x^2+y^2=4 at (1, sqrt3)`
Concept: Area Under Simple Curves
Using integration, find the area of the region bounded by the triangle whose vertices are (−1, 2), (1, 5) and (3, 4).
Concept: Area Between Two Curves
Using integration, find the area of region bounded by the triangle whose vertices are (–2, 1), (0, 4) and (2, 3).
Concept: Area Between Two Curves
Find the area bounded by the circle x2 + y2 = 16 and the line `sqrt3 y = x` in the first quadrant, using integration.
Concept: Area Under Simple Curves
