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There are two poles, one each on either bank of a river just opposite to each other. One pole is 60 m high. From the top of this pole, the angle of depression of the top and foot of the other pole are 30° and 60° respectively. Find the width of the river and height of the other pole.
Concept: Trigonometric Identities (Square Relations)
`(1 + tan^2 "A")/(1 + cot^2 "A")` is equal to ______.
Concept: Trigonometric Ratios
If 1 + sin2θ = 3 sin θ cos θ, then prove that tan θ = 1 or `1/2`.
Concept: Trigonometric Identities (Square Relations)
`(cos^2 θ)/(sin^2 θ) - 1/(sin^2 θ)`, in simplified form, is ______.
Concept: Trigonometric Identities (Square Relations)
Evaluate: 5 cosec2 45° – 3 sin2 90° + 5 cos 0°.
Concept: Trigonometric Ratios
A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy [Use π =`22/7`]
Concept: Surface Area of a Combination of Solids
If the radius of the base of a right circular cylinder is halved, keeping the height the same, then the ratio of the volume of the cylinder thus obtained to the volume of original cylinder is:
Concept: Surface Area of a Combination of Solids
In Fig. 6, OABC is a square of side 7 cm. If OAPC is a quadrant of a circle with centre O, then find the area of the shaded region. `[\text\ User=22/7]`

Concept: Surface Area of a Combination of Solids
From a solid cylinder of height 7 cm and base diameter 12 cm, a conical cavity of same height and same base diameter is hollowed out. Find the total surface area of the remaining solid. [User `pi22/7`]
Concept: Surface Area of a Combination of Solids
A cone of height 24 cm and radius of base 6 cm is made up of modelling clay. A child reshapes it in the form of a sphere. Find the radius of the sphere and hence find the surface area of this sphere.
Concept: Surface Area of a Combination of Solids
A container opened at the top and made up of a metal sheet, is in the form of a frustum of a cone of height 16 cm with radii of its lower and upper ends as 8 cm and 20 cm respectively. Find the cost of milk which can completely fill the container, at the rate of ₹ 50 per litre. Also find the cost of metal sheet used to make the container, if it costs ₹ 10 per 100 cm2. (Take π = 3⋅14)
Concept: Surface Area of a Combination of Solids
3 cubes each of 8 cm edge are joined end to end. Find the total surface area of the cuboid.
Concept: Surface Area of a Combination of Solids
The boilers are used in thermal power plants to store water and then used to produce steam. One such boiler consists of a cylindrical part in middle and two hemispherical parts at its both ends.
Length of the cylindrical part is 7 m and radius of cylindrical part is `7/2` m.
Find the total surface area and the volume of the boiler. Also, find the ratio of the volume of cylindrical part to the volume of one hemispherical part.

Concept: Surface Area of a Combination of Solids
रेखाङ्कितपदानि आधृत्य प्रश्ननिर्माणं कुरुत।
पुरा त्वया मह्यं व्याघ्रत्रयं दत्तम्।
Concept: बुद्धिर्बलवती सदा
स्थूलपदानि आधृत्य प्रश्ननिर्माणं कुरुत -
धैर्यवान् लोके परिभवं न प्राप्नोति।
Concept: सूक्तय:
Define ‘redox reaction’. Give one example.
Concept: Chemical Properties of Carbon Compounds > Oxidation
Dry raisins were soaked in water for 2 hours, to determine the percentage of water absorbed by raisins. Before final weighing of swollen raisins, the extra water left on the surface of soaked raisins was removed by:
Concept: Chemical Equations
While performing the experiment with raisins to determine the percentage of water absorbed by them, a student made following measurements:
Mass of water in the beaker = 40 g
Mass of raisins before soaking = 5 g
Mass of raisins after soaking for 2 hours = 8 g
Mass of water left in the beaker after the experiment = 35 g
The percentage of water absorbed by raisins is:
Concept: Chemical Equations
The colours of aqueous solutions of CuSO4 and FeSO4 as observed in the laboratory are:
(A) pale green and light blue respectively
(B) light blue and dark green respectively
(C) dark blue and dark green respectively
(D) dark blue and pale green respectively
Concept: Chemical Properties of Carbon Compounds > Oxidation
When hydrogen sulphide gas is passed through a blue solution of copper sulphate, a black precipitate of copper sulphide is obtained and the sulphuric acid so formed remains in the solution. The reaction is an example of a:
Concept: Types of Chemical Reactions > Double Displacement Reaction
