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Question
You are provided with the table given below. Answer the questions that follow:
| Hydrogen 1 H |
Helium 2 He |
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| Lithium 3 Li |
Beryllium 4 Be |
Boron 5 B |
Carbon 6 C |
Nitrogen 7 N |
Oxygen 8 O |
Florine 9 F |
Neon 10 Ne |
| Sodium 11 Na |
Magnesium 12 Mg |
Aluminium 13 Al |
Silicon 14 Si |
Phosphorus 15 P |
Sulphur 16 S |
Chlorine 17 Cl |
Argon 18 Ar |
| Potassium 19 K |
Calcium 20 Ca |
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- Which element has the largest size?
- Name the most non metallic element.
- Name the element with the lowest ionization potential.
- Write the formula of the sulphate of the element with atomic no. 13.
- What is the electronic configuration of the element in the fourth period that forms a dipositive ion?
- Write the formula of the phosphate of the element in fourth period, second group.
Long Answer
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Solution
- Atomic size increases down a group (due to more shells) and decreases left to right across a period (due to higher nuclear charge). Potassium, being at the bottom-left, is the largest.
- Fluorine (F)
- Potassium (K)
- Al2(SO4)3.
- The element in the fourth period that forms a dipositive ion M2+ must have 2 valence electrons. This element is calcium (Ca), located in Period 4, Group 2.
- Ca3(PO4)2
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