Question

Xenon crystallises in fcc lattice and the edge length of unit cell is 620 pm. What is the radius of Xe atom?

Options

• 438.5 pm

• 219.2 pm

• 265.5 pm

• 536.9 pm

Answer 1

219.2 pm

Explanation:

Given,

Edge length of unit cell (a) = 620 pm

For fcc we know,

Radius (r) = `"a"/(2sqrt(2)) = 620/(2sqrt2)` pm

= `310/1.414` pm

= 219.2 pm