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प्रश्न
Xenon crystallises in fcc lattice and the edge length of unit cell is 620 pm. What is the radius of Xe atom?
पर्याय
438.5 pm
219.2 pm
265.5 pm
536.9 pm
MCQ
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उत्तर
219.2 pm
Explanation:
Given,
Edge length of unit cell (a) = 620 pm
For fcc we know,
Radius (r) = `"a"/(2sqrt(2)) = 620/(2sqrt2)` pm
= `310/1.414` pm
= 219.2 pm
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Packing of Particles in Crystal Lattice
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