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Question
x = (cosec A + cot A) (1 − cos A).
Assertion (A): x = sin A.
Reason (R): \[x = \left(\frac{1}{\sin A} + \frac{\cos A}{\sin A}\right)(1 - \cos A)\]
\[{} = \frac{\sin^2 A}{\sin A} = \sin A\]
Options
A is true, R is false.
A is false, R is true.
Both A and R are true and R is the correct reason for A.
Both A and R are true and R is the incorrect reason for A.
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Solution
Both A and R are true and R is the correct reason for A.
Explanation:
Given, \[x = (\operatorname{cosec} A + \cot A)(1 - \cos A)\]
\[\Rightarrow x = \left(\frac{1}{\sin A} + \frac{\cos A}{\sin A}\right)(1 - \cos A)\]
\[{} = \left(\frac{1 + \cos A}{\sin A}\right)(1 - \cos A)\]
\[{} = \frac{(1 + \cos A)(1 - \cos A)}{\sin A}\]
\[{} = \left(\frac{1 - \cos^2 A}{\sin A}\right)\]
\[{} = \left(\frac{\sin^2 A}{\sin A}\right)\]
\[{} = \sin A.\]
∴ Both A and R are true and R is correct reason for A.
