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`X^2-4x+1=0` - Mathematics

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Question

`x^2-4x+1=0`

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Solution

`x^2-4x+1=0` 

⇒`x^2-4x=1` 

⇒`x^2-2xx x xx2+2^2=-1+2^2`          (Adding `2^2`on both sides)

⇒`(x-2)^2=+-sqrt3` 

⇒`x-2=+-sqrt3`                    (Taking square root on the both sides)

⇒`x-2=sqrt3  or  x-2=-sqrt3` 

⇒`x=2+sqrt3  or  x=2-sqrt3` 

Hence, `2+sqrt3 and 2-sqrt3`  are the roots of the given equation.

 

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Chapter 10: Quadratic Equations - Exercises 2

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 10 Quadratic Equations
Exercises 2 | Q 2

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