Question

`x^2-4x+1=0`

Answer 1

`x^2-4x+1=0` 

⇒`x^2-4x=1` 

⇒`x^2-2xx x xx2+2^2=-1+2^2`          (Adding `2^2`on both sides)

⇒`(x-2)^2=+-sqrt3` 

⇒`x-2=+-sqrt3`                    (Taking square root on the both sides)

⇒`x-2=sqrt3  or  x-2=-sqrt3` 

⇒`x=2+sqrt3  or  x=2-sqrt3` 

Hence, `2+sqrt3 and 2-sqrt3`  are the roots of the given equation.