Advertisements
Advertisements
Question
Writing \[x\cos\left(\frac{y}{x}\right)\frac{dy}{dx}=y\cos\left(\frac{y}{x}\right)+x\] in standard form gives which expression?
Options
\[\frac{dy}{dx}=y\cos\left(\frac{y}{x}\right)+x\cos\left(\frac{y}{x}\right)\]
\[\frac{dy}{dx}=\frac{x\cos\left(\frac{y}{x}\right)}{y\cos\left(\frac{y}{x}\right)+x}\]
\[\frac{dy}{dx}=\frac{y\cos\left(\frac{y}{x}\right)+x}{x\cos\left(\frac{y}{x}\right)}\]
\[\frac{dy}{dx}=\frac{y+x}{\cos\left(\frac{y}{x}\right)}\]
MCQ
Advertisements
Solution
Divide both sides by \[x\cos\left(\frac{y}{x}\right)\]. This gives \[\frac{dy}{dx}=\frac{y\cos\left(\frac{y}{x}\right)+x}{x\cos\left(\frac{y}{x}\right)}\], which is of the form \[\frac{dy}{dx}=F(x,y)\].
shaalaa.com
Is there an error in this question or solution?
