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Question
Write the zeros of the polynomial `f(x) = x^2 – x – 6`.
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Solution
`f(x) = x^2 – x – 6`
`= x^2 – 3x + 2x – 6`
`= x(x – 3) + 2(x – 3)`
`= (x – 3) (x + 2)`
`f(x) = 0 ⇒ (x – 3) (x + 2) = 0`
`⇒ (x – 3) = 0 or (x + 2) = 0`
`⇒ x = 3 or x = –2`
So, the zeroes of f(x) are 3 and –2.
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