Sum
Write the symbolic form of the following switching circuit construct its switching table and interpret it.
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Solution
Let p: the switch S1 is closed
q: the switch S2 is closed
∼ p: the switch S1‘ is closed or the switch S1 is open.
∼ q: the switch S2′ is closed or the switch S2 is open.
Then the symbolic form of the given circuit is:
p ∨ (∼ p ∧ ∼ q) ∨ (p ∧ q)
Switching Table
p | q | ∼p | ∼q | ∼p∧∼q | p∧q | p∨(∼p∧∼q)∨(p∧q) |
1 | 1 | 0 | 0 | 0 | 1 | 1 |
1 | 0 | 0 | 1 | 0 | 0 | 1 |
0 | 1 | 1 | 0 | 0 | 0 | 0 |
0 | 0 | 1 | 1 | 1 | 0 | 1 |
Since the final column contains ‘0’ when p is 0 and q is ‘1’, otherwise it contains ‘1’.
Hence, the lamp will not glow when S1 is OFF and S2 is ON, otherwise, the lamp will glow.
Concept: Application of Logic to Switching Circuits
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