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Question
Write the reaction when ethylamine is treated with an excess of ethyl bromide.
Chemical Equations/Structures
One Line Answer
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Solution
When ethylamine (C2H5NH2) is treated with excess ethyl bromide (C2H5Br), it undergoes alkylation, forming tetraethylammonium bromide (C2H5)4N+Br−.
\[\ce{\underset{Ethylamine}{C2H5NH2} ->[C2H5Br][excess] \underset{Tetraethylammonium bromide}{(C2H5)4N^+Br^-}}\]
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