Question

Write the reaction when ethylamine is treated with an excess of ethyl bromide.

Answer 1

When ethylamine (C₂H₅NH₂) is treated with excess ethyl bromide (C₂H₅Br), it undergoes alkylation, forming tetraethylammonium bromide (C₂H₅)₄N⁺Br⁻.

\[\ce{\underset{Ethylamine}{C2H5NH2} ->[C2H5Br][excess] \underset{Tetraethylammonium bromide}{(C2H5)4N^+Br^-}}\]