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Question
Write the output of the queries based on the table, TECH_COURSE given below:
| Table: TECH_COURSE | ||||
| CID | CNAME | FEES | STARTDATE | TID |
| C201 | Animation and VFX | 12000 | 2022-07-02 | 101 |
| C202 | CADD | 15000 | 2021-11-15 | NULL |
| C203 | DCA | 10000 | 2020-10-01 | 102 |
| C204 | DDTP | 9000 | 2021-09-15 | 104 |
| C205 | Mobile Application Development |
18000 | 2022-11-01 | 101 |
| C206 | Digital Marketing | 16000 | 2022-07-25 | 103 |
- SELECT DISTINCT TID FROM TECH_COURSE;
- SELECT TID, COUNT(*), MIN(FEES) FROM TECH_COURSE GROUP BY TID HAVING COUNT(TID)>1;
- SELECT CNAME FROM TECH_COURSE WHERE FEES>15000 ORDER BY CNAME;
- SELECT AVG(FEES) FROM TECH_COURSE WHERE FEES BETWEEN 15000 AND 17000;
Short/Brief Note
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Solution
DISTINCT TID 101 NULL 102 104 103
TID COUNT(*) MIN(FEES) 101 2 12000
CNAME Digital Marketing Mobile Application Development - 15500.00
shaalaa.com
GROUP BY Clause in SQL
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