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Question
Write the given quadratic equation in standard form and also write the values of a, b and c.
4y2 – 3y = –7
Sum
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Solution
Given equation is 4y2 – 3y = –7
∴ 4y2 – 3y + 7 = 0
Comparing the above equation with ay2 + by + c = 0, we get
a = 4, b = –3, c = 7
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