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Question
Write the equation of the lines through the point (1, −1) parallel to x + 3y − 4 = 0
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Solution
Any line parallel to x + 3y – 4 = 0 will be of the form x + 3y + k = 0.
It passes through (1, –1)
⇒ 1 – 3 + k = 0
⇒ k = 2
So the required line is x + 3y + 2 = 0
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