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Question
Write second and third term of an A.P. whose first term is 6 and common difference is – 3.
Sum
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Solution
a = 6, d = – 3 .....[Given]
∴ t1 = a = 6
t2 = t1 + d
∴ t2 = 6 + (– 3)
∴ t2 = 6 – 3
∴ t2 = 3
t3 = t2 + d
∴ t3 = 3 + (– 3)
∴ t3 = 3 – 3
∴ t3 = 0
∴ t2 = 3 and t3 = 0
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