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Write the Length (Magnitude) of a Vector Whose Projections on the Coordinate Axes Are 12, 3 and 4 Units.

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Question

Write the length (magnitude) of a vector whose projections on the coordinate axes are 12, 3 and 4 units.

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Solution

Given: Projection on the coordinate axes are 12, 3, 4 units.
Therefore, Length of vector
\[= \sqrt{{12}^2 + 3^2 + 4^2}\]
= \[\sqrt{169}\]
= 13

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Magnitude and Direction of a Vector
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Chapter 22: Algebra of Vectors - Very Short Answers [Page 76]

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R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 22 Algebra of Vectors
Very Short Answers | Q 20 | Page 76
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