Question

Write an assembly language program that multiply two 8 bit hex numbers stored in memory locations 9404H and 9405H. Store the two byte result in consecutive memory locations 9606H begining with lower order byte.

Answer 1

      LXI H, 0000H  ; Initialize HL pair to 0000H (to store result)
      LDA 9404H     ; Load first number into Accumulator
      MOV B, A      ; Move first number to Register B (Multiplicand)
      LDA 9405H     ; Load second number into Accumulator
      MOV C, A      ; Move second number to Register C (Multiplier/Counter)
      LXI D, 0000H  ; Clear DE pair
      MOV E, B      ; Move Multiplicand to Register E for 16-bit addition

LOOP: DAD D         ; Add DE to HL (HL = HL + DE)
      DCR C         ; Decrement the multiplier counter
      JNZ LOOP      ; If C is not zero, repeat addition

      SHLD 9606H    ; Store 16-bit result (L-byte at 9606H, H-byte at 9607H)
      HLT           ; Stop execution