Advertisements
Advertisements
Question
Write a Pythagorean triplet whose one member is 18.
Advertisements
Solution
The three numbers of Pythagorean triples are 2m, m2 - 1 and m2 + 1.
Here, 2m = 18
So, m = 9
Second number (m2 - 1)
= (9)2 - 1
= 81 - 1
= 80
Third number (m2 + 1)
= (9)2 + 1
= 81 + 1
= 82
Hence the Pythagorean triplet is (18, 80, 82).
APPEARS IN
RELATED QUESTIONS
Find the square of the given number.
86
What will be the units digit of the square of the following number?
52
From the pattern, we can say that the sum of the first n positive odd numbers is equal to the square of the n-th positive number. Putting that into formula:
1 + 3 + 5 + 7 + ... n = n2, where the left hand side consists of n terms.
Observe the following pattern
22 − 12 = 2 + 1
32 − 22 = 3 + 2
42 − 32 = 4 + 3
52 − 42 = 5 + 4
and find the value of
992 − 962
Which of the following triplet pythagorean?
(10, 24, 26)
Find the squares of the following numbers using diagonal method:
98
The sides of a right triangle whose hypotenuse is 17 cm are ______ and ______.
The sum of two perfect squares is a perfect square.
All numbers of a pythagorean triplet are odd.
Find the length of the side of a square if the length of its diagonal is 10 cm.
