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Question
Write a Pythagorean triplet whose one member is 18.
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Solution
The three numbers of Pythagorean triples are 2m, m2 - 1 and m2 + 1.
Here, 2m = 18
So, m = 9
Second number (m2 - 1)
= (9)2 - 1
= 81 - 1
= 80
Third number (m2 + 1)
= (9)2 + 1
= 81 + 1
= 82
Hence the Pythagorean triplet is (18, 80, 82).
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