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Question
Work out the following division:
9x2y2(3z − 24) ÷ 27xy(z − 8)
Sum
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Solution
9x2y2(3z − 24) ÷ 27xy(z − 8)
= `(9x^2y^2(3 z - 24))/(27xy(z - 8))`
= `(9x^2y^2* 3 (z - 8))/(27xy (z - 8))`
= `(27x^2y^2 (z - 8))/(27 xy (z - 8))`
= xy
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