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Without using trigonometric tables, prove that: cot 34° – tan 56° = 0

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Question

Without using trigonometric tables, prove that:

cot 34° – tan 56° = 0

Theorem
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Solution

Given: cot 34° – tan 56°

To Prove: cot 34° – tan 56° = 0

Proof [Step-wise]:

1. Note that 34° = 90° – 56°.

2. Therefore cot 34° = cot (90° – 56°).

3. Use the complementary-angle identity cot (90° – θ) = tan θ to get cot (90° – 56°) = tan 56°.

4. Substitute: cot 34° – tan 56°

= tan 56° – tan 56° 

= 0

Hence, cot 34° – tan 56° = 0, as required.

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Chapter 12: Trigonometric Ratios of Some Complemantary Angles - EXERCISE 12 [Page 590]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 12 Trigonometric Ratios of Some Complemantary Angles
EXERCISE 12 | Q 2. (iv) | Page 590
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