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Question
Without using trigonometric tables, evaluate:
`(sin 26^circ)/(cos 64^circ)`
Evaluate
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Solution
Given: `(sin 26^circ)/(cos 64^circ)`
cos 64° = sin (90° – 64°) = sin 26° ...(Using cos (90° – θ) = sin θ)
Therefore, `(sin 26^circ)/(cos 64^circ) = (sin 26^circ)/(sin 26^circ)`
= 1
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