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Question
Without using set squares or protractor.
(i) Construct a ΔABC, given BC = 4 cm, angle B = 75° and CA = 6 cm.
(ii) Find the point P such that PB = PC and P is equidistant from the side BC and BA. Measure AP.
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Solution
(i) Draw BC = 4 cm. Draw BA at B such that ∠ABC = 75°. Cut CA = 6 cm. Then ΔABC is the required Δ.
(ii) Draw single bisector of ∠B. Draw ⊥ bisector of BC. Their point of intersection (P) is the requisite point.
AP = 3·9 cm.
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(i) Construct Δ ABC, in which BC = 8 cm, AB = 5 cm, ∠ ABC = 60°.
(ii) Construct the locus of point inside the triangle which are equidistant from BA and BC.
(iii) Construct the locus of points inside the triangle which are equidistant from B and C.
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